When a student's rank is given from both ends, total students = rank from top + rank from bottom − 1. Here, total = 34 + 38 − 1 = 71. Answer: (C) 71

H→L (+4), N→K (−3). N→R (+4), Y→V (−3). O→S (+4), U→R (−3). Number: 9→−3 (−12), 4→−8 (−12). So 13→1 (−12). Answer: (C) SR 1

Original: 1 7 3 2 5 9 6 Ascending: 1 2 3 5 6 7 9 Comparing positions: 1→1 ✓, 7→2 ✗, 3→3 ✓, 2→5 ✗, 5→6 ✗, 9→7 ✗, 6→9 ✗ Positions 1 and 3 remain unchanged. Count = Two. Answer: (C) Two

The correct answer is (C) 245. Interchange rule: \(+ \leftrightarrow \div\), \(- \leftrightarrow \times\). Original: \(850 + 34 \times 15 - 12 \div 400\) After swap: \(850 \div 34 - 15 \times 12 + 400\) Apply BODMAS: \(850 \div 34 = 25\) and \(15 \times 12 = 180\). So expression = \(25 - 180 + 400 = 245\). Exam Tip: First replace every operator exactly as the rule says, then solve strictly by BODMAS — never mix both steps.

Total = 60. Shivani is 40th from right = 60 − 40 + 1 = 21st from left. Sneha is 26th from left. People between them = 26 − 21 − 1 = 4. Answer: (C) 4

P − T → P is father of T T * C → T is brother of C (so P is also father of C) C + D → C is sister of D (so P is also father of D) D \(\div\) E → D is mother of E P is father of D, D is mother of E → P is maternal grandfather (Mother's father) of E. Answer: (A) Mother's father

Differences: 41−36=5, 51−41=10, 66−51=15, 86−66=20 Pattern: differences increase by 5 each time. Next difference = 25. So ? = 86 + 25 = 111. Answer: (C) 111

The correct answer is (C). Newton is the unit of weight (force). Pascal is the unit of pressure. The analogy is: Newton is to weight as Pascal is to pressure. Kelvin (A) is temperature. Kg/m³ (B) is density. Kilogram (D) is mass. Pascal = Newton/m², showing pressure as force per unit area. Exam Tip: Pascal (Pa) = N/m². Remember: 1 Pa = 1 Newton of force on 1 square meter. Named after Blaise Pascal.

The correct answer is (B) HL – DE. Three of the four pairs follow a consistent gap pattern — first cluster has an internal gap of +4, and the second cluster has a gap of +2 (mod 26): • (A) DH – ZB: D→H = +4, Z→B = +2 (26 → 28 → wraps to 2) • (C) CG – YA: C→G = +4, Y→A = +2 (25 → 27 → wraps to 1) • (D) UY – QS: U→Y = +4, Q→S = +2 In (B) HL – DE, the first cluster H→L = +4 fits, but the second cluster D→E = +1, not +2. So HL – DE breaks the pattern and is the odd one out. Exam Tip: For letter-cluster odd-one-out, compute the internal gap within each cluster in both halves. Here the signature is (+4, +2).

The correct answer is (A) 3. Number the seats 1 to 7 from left to right (people facing north, so position 7 is at the right end). • "Only 2 people to the right of F" → F is at position 5. • "3 people between F and A" → A is at position 1 (positions 2, 3, 4 lie between them). • "E and C are both immediate neighbours of G" → G is flanked by E and C. F blocks position 5, so G must be at position 3 with E and C at positions 2 and 4. • "C is not an immediate neighbour of A" → C ≠ position 2, so C = 4 and E = 2. • "D sits immediately to the left of B" → the remaining positions 6 and 7 get D and B respectively, giving D = 6, B = 7. Final arrangement: A(1), E(2), G(3), C(4), F(5), D(6), B(7). Between D (position 6) and E (position 2) lie positions 3, 4, 5 → G, C, F, i.e. 3 people. Exam Tip: In 'facing north' linear seating, the person's right side matches the right side of the row; lock down positions with fixed counts (like "only 2 to the right") first.

The correct answer is (B) Two. Number the positions 1 (bottom) to 7 (top) of the stack. • "Only A is kept above J" → A is the only box higher than J, so J = position 6 and A = position 7. • "Only K is kept below J" → K is the box directly below J, i.e. K = position 5. • "Two boxes between I and C" → |position(I) − position(C)| = 3. Among the remaining slots 1–4 the only such pair is {1, 4}, so one of I/C is at 1 and the other at 4. • "D is not immediately above C" → the box at position (C + 1) is not D. This rules out D at position 2 when C = 1, giving C = 1, B = 2, D = 3, I = 4. Final stack (bottom → top): C(1), B(2), D(3), I(4), K(5), J(6), A(7). Between B (position 2) and K (position 5) lie positions 3 and 4 → D and I, i.e. 2 boxes. Exam Tip: In vertical-stack puzzles, anchor the top/bottom block first (here A–J–K), then fit the rest using distance clues.

The correct answer is (C) 7. Series: 5 3 2 9 7 2 4 5 3 4 6 3 9 8 3 3 2 8 9 3 4 5 7 6 Find odd numbers preceded by odd AND followed by even: Pos 2: 5-3-2 ✓ Pos 5: 9-7-2 ✓ Pos 9: 5-3-4 ✓ Pos 13: 3-9-8 ✓ Pos 16: 3-3-2 ✓ Pos 20: 9-3-4 ✓ Pos 23: 5-7-6 ✓ Total = 7 such odd numbers.

The correct answer is (A) P. Arranging the six friends clockwise around the table: position 1 Q, position 2 U, position 3 P, position 4 S, position 5 T, position 6 R. Since P sits second to the right of Q, P is two seats clockwise from Q (position 3). R sits immediately counter-clockwise from Q (position 6). S sits directly opposite Q (position 4). T cannot be a neighbour of P or Q, so T takes position 5. U fills the remaining position 2, which places U immediately to the left of P. Therefore the person immediately to the right of U is P.

The correct answer is (C) DTZ. Analyse each letter position separately between consecutive terms: - 1st letter: P(16) → M(13) → J(10) → G(7) → ? — a consistent -3 shift, so next is G(7) - 3 = D(4). - 2nd letter: P(16) → Q(17) → R(18) → S(19) → ? — a consistent +1 shift, so next is S(19) + 1 = T(20). - 3rd letter: R(18) → T(20) → V(22) → X(24) → ? — a consistent +2 shift, so next is X(24) + 2 = Z(26). Combining D, T, Z gives DTZ. Exam Tip: When three-letter series do not share a single rule, break each term into positions and track the shift at each position separately.

The correct answer is (A) I25K. Letter pattern: each term contains two letters separated by one letter (a gap of +2 in alphabetical position), and the first letter of every new term equals the second letter of the previous term — A-C → C-E → E-G → G-I → I-K. Number pattern: the middle numbers are squares of consecutive natural numbers — 1 = 1², 4 = 2², 9 = 3², 16 = 4², so the next number is 5² = 25. Combining both patterns, the missing term is I25K.

The correct answer is (A) 4. Series: 3 5 4 9 7 1 1 6 4 2 3 3 4 2 7 8 6 8 5 5 1 2 9 2 Find odd numbers preceded by odd AND followed by even: Pos 2: 3-5-4 ✓ Pos 7: 1-1-6 ✓ Pos 12: 3-3-4 ✓ Pos 21: 5-1-2 ✓ Total = 4 such odd numbers.

The correct answer is (A) Three. Series: 6 1 7 6 8 5 2 7 6 9 2 3 4 8 3 2 5 9 4 1 7 6 8 3 1 9 Find even numbers preceded by even AND followed by odd: Pos 5: 6-8-5 ✓ Pos 14: 4-8-3 ✓ Pos 23: 6-8-3 ✓ Total = 3 such even numbers.

The correct answer is (C) SUPT. In this analogy, each letter of the original word is shifted forward by 7 positions in the English alphabet. Verify with JLGK → QSNR: J(10) + 7 = Q(17) L(12) + 7 = S(19) G(7) + 7 = N(14) K(11) + 7 = R(18) Apply the same +7 shift to LNIM: L(12) + 7 = S(19) N(14) + 7 = U(21) I(9) + 7 = P(16) M(13) + 7 = T(20) So LNIM → SUPT, which is option (C). Exam Tip: For letter-analogy questions, calculate the positional shift from the clearest example pair first, then apply the same shift to the target word.

The correct answer is (C). From the clues, D and F are at positions 1 and 7 (5 people between them), G is at position 6 (immediately left of F), and A is at position 4. The arrangement is D(1), E(2), B(3), A(4), C(5), G(6), F(7), giving 3 people to the right of A.

The correct answer is (A) rp. Comparing the two sentences: 'stop disturbing people' = 'ts ck rp' 'people need peace' = 'cd ok rp' Common word: 'people' appears in both Common code: 'rp' appears in both Therefore, 'people' is coded as 'rp'. Verify: 'stop disturbing people' has 3 words → 'ts ck rp' has 3 codes ✓ 'people need peace' has 3 words → 'cd ok rp' has 3 codes ✓ Common word 'people' → common code 'rp' ✓ Exam Tip: Coding-decoding: find common words between sentences to identify their codes. The word appearing in both sentences maps to the code appearing in both.